JEE MAIN - Physics (2024 - 9th April Morning Shift - No. 14)
A heavy iron bar, of weight $$W$$ is having its one end on the ground and the other on the shoulder of a person. The bar makes an angle $$\theta$$ with the horizontal. The weight experienced by the person is :
$$W \sin \theta$$
$$W$$
$$\frac{W}{2}$$
$$W \cos \theta$$
Explanation
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$$\begin{aligned} & m g \times \frac{L}{2} \cos \theta=N \times L \cos \theta \\ & \Rightarrow \quad N=\frac{m g}{2}=\frac{W}{2} \end{aligned}$$
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