JEE MAIN - Physics (2024 - 9th April Evening Shift - No. 8)
Five charges $$+q,+5 q,-2 q,+3 q$$ and $$-4 q$$ are situated as shown in the figure. The electric flux due to this configuration through the surface $$S$$ is :
_9th_April_Evening_Shift_en_8_1.png)
$$\frac{q}{\epsilon_0}$$
$$\frac{3 q}{\epsilon_0}$$
$$\frac{5 q}{\epsilon_0}$$
$$\frac{4 q}{\epsilon_0}$$
Explanation
$$\begin{aligned}
\phi & =\frac{q_{\mathrm{en}}}{\epsilon_0} \\
& =\frac{(5+1-2) q}{\epsilon_0} \\
& =\frac{4 q}{\epsilon_0}
\end{aligned}$$
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