JEE MAIN - Physics (2024 - 9th April Evening Shift - No. 23)
To determine the resistance (R) of a wire, a circuit is designed below. The $$V$$-$$I$$ characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in figure. The value of $R$ is _________ $$\Omega$$.
_9th_April_Evening_Shift_en_23_1.png)
Answer
2500
Explanation
$$\begin{aligned}
& R_{\text {net }}=\frac{1}{\text { Slope }}=\frac{8}{4} \times 10^3=2 \times 10^3 \\
& \Rightarrow 2=\frac{10 R}{10+R} \\
& \Rightarrow 20+2 R=10 R \\
& \Rightarrow 8 R=20 \\
& \Rightarrow R=2.5 \mathrm{k} \Omega \\
& \quad=2500 ~\Omega
\end{aligned}$$
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