JEE MAIN - Physics (2024 - 9th April Evening Shift - No. 22)
An electric field $$\vec{E}=(2 x \hat{i}) N C^{-1}$$ exists in space. A cube of side $$2 \mathrm{~m}$$ is placed in the space as per figure given below. The electric flux through the cube is ______ $$\mathrm{Nm}^2 / \mathrm{C}$$.
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Answer
16
Explanation
Flux will only be due to surfaces having area vector parallel to $$x$$ - axis
$$\begin{aligned} \therefore \quad & \phi_{\text {net }}=A[8-4] \\ & =4 A=4 \times 4=16 \end{aligned}$$
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