JEE MAIN - Physics (2024 - 9th April Evening Shift - No. 20)
The following figure represents two biconvex lenses $$L_1$$ and $$L_2$$ having focal length $$10 \mathrm{~cm}$$ and $$15 \mathrm{~cm}$$ respectively. The distance between $$L_1$$ & $$L_2$$ is :
_9th_April_Evening_Shift_en_20_1.png)
25 cm
35 cm
10 cm
15 cm
Explanation
Parallel rays are focussed by convex lens and viceversa.
$$\begin{aligned} \therefore \quad L_1 L_2 & =f_1+f_2 \\ & =10+15=25 \mathrm{~cm} \end{aligned}$$
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