JEE MAIN - Physics (2024 - 9th April Evening Shift - No. 2)

JEE Main 2024 (Online) 9th April Evening Shift Physics - Semiconductor Question 20 English

In the truth table of the above circuit the value of X and Y are :

1, 1
0, 1
1, 0
0, 0

Explanation

$$\begin{aligned} & Y=\overline{A B+\overline{A B}} \\ & \text { for } A=0, B=1, Y=1 \\ & \text { for } A=1, B=0, Y=1 \end{aligned}$$

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