JEE MAIN - Physics (2024 - 9th April Evening Shift - No. 18)
A square loop of side $$15 \mathrm{~cm}$$ being moved towards right at a constant speed of $$2\mathrm{~cm} / \mathrm{s}$$ as shown in figure. The front edge enters the $$50 \mathrm{~cm}$$ wide magnetic field at $$t=0$$. The value of induced emf in the loop at $$t=10 \mathrm{~s}$$ will be :
_9th_April_Evening_Shift_en_18_1.png)
zero
4.5 mV
0.3 mV
3 mV
Explanation
Time taken to cross the field region
$$=\frac{50}{2}=25 \mathrm{~s}$$
At $$10 \mathrm{~s}$$ the loop is inside field and flux is not changing.
$$\therefore \quad \varepsilon_{\text {induced }}=0$$
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