JEE MAIN - Physics (2024 - 8th April Morning Shift - No. 7)

The output $$\mathrm{Y}$$ of following circuit for given inputs is :

JEE Main 2024 (Online) 8th April Morning Shift Physics - Semiconductor Question 14 English

$$A \cdot B$$
$$\bar{A} \cdot B$$
$$\Lambda \cdot B(\Lambda+B)$$
0

Explanation

JEE Main 2024 (Online) 8th April Morning Shift Physics - Semiconductor Question 14 English Explanation

Comments (0)

Advertisement