JEE MAIN - Physics (2024 - 8th April Morning Shift - No. 28)
A parallel beam of monochromatic light of wavelength $$600 \mathrm{~nm}$$ passes through single slit of $$0.4 \mathrm{~mm}$$ width. Angular divergence corresponding to second order minima would be _________ $$\times 10^{-3} \mathrm{~rad}$$.
Answer
6
Explanation
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$$\begin{aligned} \theta & =(2)\left(\frac{2 \lambda}{a}\right) \\ & =\frac{4 \lambda}{a}=\frac{4 \times 600 \times 10^{-9}}{0.4 \times 10^{-3}} \\ & =6 \times 10^{-3} \end{aligned}$$
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