JEE MAIN - Physics (2024 - 8th April Morning Shift - No. 17)

Correct Bernoulli's equation is (symbols have their usual meaning) :
$$P+\frac{1}{2} \rho g h+\frac{1}{2} \rho v^2=$$ constant
$$P+m g h+\frac{1}{2} m v^2=$$ constant
$$P+\rho g h+\rho v^2=$$ constant
$$P+\rho g h+\frac{1}{2} \rho v^2=$$ constant

Explanation

Bernoulli's equation relates the pressure, velocity, and height in a flowing fluid and is derived from the principle of conservation of energy. The correct form of Bernoulli's equation is:

$$P + \rho g h + \frac{1}{2} \rho v^2 = \text{constant}$$

where:

  • P is the pressure within the fluid.
  • $\rho$ is the density of the fluid.
  • g is the acceleration due to gravity.
  • h is the height above a reference point.
  • v is the velocity of the fluid.

Looking at the options given:

  1. Option A: $$P + \frac{1}{2} \rho g h + \frac{1}{2} \rho v^2 = \text{constant}$$
  2. Option B: $$P + m g h + \frac{1}{2} m v^2 = \text{constant}$$
  3. Option C: $$P + \rho g h + \rho v^2 = \text{constant}$$
  4. Option D: $$P + \rho g h + \frac{1}{2} \rho v^2 = \text{constant}$$

Option D correctly represents Bernoulli's equation in its proper form. Therefore, the correct answer is:

Option D

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