JEE MAIN - Physics (2024 - 8th April Morning Shift - No. 17)
Correct Bernoulli's equation is (symbols have their usual meaning) :
$$P+\frac{1}{2} \rho g h+\frac{1}{2} \rho v^2=$$ constant
$$P+m g h+\frac{1}{2} m v^2=$$ constant
$$P+\rho g h+\rho v^2=$$ constant
$$P+\rho g h+\frac{1}{2} \rho v^2=$$ constant
Explanation
Bernoulli's equation relates the pressure, velocity, and height in a flowing fluid and is derived from the principle of conservation of energy. The correct form of Bernoulli's equation is:
$$P + \rho g h + \frac{1}{2} \rho v^2 = \text{constant}$$
where:
- P is the pressure within the fluid.
- $\rho$ is the density of the fluid.
- g is the acceleration due to gravity.
- h is the height above a reference point.
- v is the velocity of the fluid.
Looking at the options given:
- Option A: $$P + \frac{1}{2} \rho g h + \frac{1}{2} \rho v^2 = \text{constant}$$
- Option B: $$P + m g h + \frac{1}{2} m v^2 = \text{constant}$$
- Option C: $$P + \rho g h + \rho v^2 = \text{constant}$$
- Option D: $$P + \rho g h + \frac{1}{2} \rho v^2 = \text{constant}$$
Option D correctly represents Bernoulli's equation in its proper form. Therefore, the correct answer is:
Option D
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