JEE MAIN - Physics (2024 - 6th April Morning Shift - No. 24)
Three infinitely long charged thin sheets are placed as shown in figure. The magnitude of electric field at the point $$P$$ is $$\frac{x \sigma}{\epsilon_0}$$. The value of $$x$$ is _________ (all quantities are measured in SI units).
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Answer
2
Explanation
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$\begin{aligned} \overrightarrow{\mathrm{E}}_{\mathrm{p}} & =\left(\frac{\sigma}{2 \varepsilon_0}+\frac{2 \sigma}{2 \varepsilon_0}+\frac{\sigma}{2 \varepsilon_0}\right)(-\hat{\mathrm{i}}) \\\\ & =-\frac{2 \sigma}{\varepsilon_0} \hat{\mathrm{i}}\end{aligned}$Comments (0)
