JEE MAIN - Physics (2024 - 6th April Morning Shift - No. 19)
A sample contains mixture of helium and oxygen gas. The ratio of root mean square speed of helium and oxygen in the sample, is :
$$\frac{1}{2 \sqrt{2}}$$
$$\frac{1}{4}$$
$$\frac{2 \sqrt{2}}{1}$$
$$\frac{1}{32}$$
Explanation
$$\begin{aligned}
& v=\sqrt{\frac{3 R T}{M}} \\
& \Rightarrow \frac{v_{\mathrm{H}_{\mathrm{e}}}}{v_{\mathrm{O}_2}}=\sqrt{\frac{M_{\mathrm{o}_2}}{M_{\mathrm{H}_e}}}=\frac{2 \sqrt{2 }}{1}
\end{aligned}$$
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