JEE MAIN - Physics (2024 - 5th April Morning Shift - No. 27)
An ac source is connected in given series LCR circuit. The rms potential difference across the capacitor of $$20 \mu \mathrm{F}$$ is __________ V.
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Answer
50
Explanation
$$\begin{aligned}
& \left(V_{r m s}\right)_c=\frac{V_{r m s}}{Z} X_c \\
& =\frac{50}{\sqrt{(500-100)^2+300^2}} \times 500 \\
& =50 \mathrm{~V}
\end{aligned}$$
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