JEE MAIN - Physics (2024 - 5th April Morning Shift - No. 25)
In the experiment to determine the galvanometer resistance by half-deflection method, the plot of $$1 / \theta$$ vs the resistance (R) of the resistance box is shown in the figure. The figure of merit of the galvanometer is _________ $$\times 10^{-1} \mathrm{~A} /$$ division. [The source has emf $$2 \mathrm{~V}$$]
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Answer
5
Explanation
$$\frac{1}{3} \mathrm{~A} \longrightarrow \frac{1}{2} \mathrm{div}$$
$$\frac{1}{2} \mathrm{~A} \longrightarrow \frac{2}{3} \mathrm{div}$$
$$\text { Figure of merit }=\frac{\Delta i}{\Delta \theta} \quad \begin{aligned} & \frac{\frac{1}{2}--}{\frac{2}{3}-\frac{1}{2}} \\ &=0.5 \\ &=5 \times 10^{-1} \mathrm{~A} / \mathrm{div} \end{aligned}$$
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