To find the angle between the vector $$\vec{Q}$$ and the resultant of $$(2 \vec{Q}+2 \vec{P})$$ and $$(2 \vec{Q}-2 \vec{P})$$, we first find the resultant vector of $$(2 \vec{Q}+2 \vec{P})$$ and $$(2 \vec{Q}-2 \vec{P})$$.

The resultant vector of $$(2 \vec{Q}+2 \vec{P})$$ and $$(2 \vec{Q}-2 \vec{P})$$ can be simply found by adding these two vectors:

Now, we need to find the angle between the vector $$\vec{Q}$$ and this resultant vector $$4\vec{Q}$$. Since the resultant vector is just a scaled version of $$\vec{Q}$$, they are in the same direction. The angle between any vector and another vector that is a scaled version of the first vector is always $$0^\circ$$, because they are parallel to each other.

Therefore, the angle between $$\vec{Q}$$ and the resultant of $$(2 \vec{Q}+2 \vec{P})$$ and $$(2 \vec{Q}-2 \vec{P})$$ is $$0^\circ$$.

So, the correct option is:

Option B: $$0^\circ$$