JEE MAIN - Physics (2024 - 5th April Evening Shift - No. 8)
A series LCR circuit is subjected to an ac signal of $$200 \mathrm{~V}, 50 \mathrm{~Hz}$$. If the voltage across the inductor $$(\mathrm{L}=10 \mathrm{~mH})$$ is $$31.4 \mathrm{~V}$$, then the current in this circuit is _______.
10 A
10 mA
68 A
63 A
Explanation
$$\begin{aligned}
&V_L=I(\omega L)=31.4\\
&\begin{aligned}
\Rightarrow \quad I & =\frac{31.4}{2 \times 3.14 \times 50 \times 10 \times 10^{-3}} \\
& =10 \mathrm{~A}
\end{aligned}
\end{aligned}$$
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