JEE MAIN - Physics (2024 - 5th April Evening Shift - No. 23)
In a single slit experiment, a parallel beam of green light of wavelength $$550 \mathrm{~nm}$$ passes through a slit of width $$0.20 \mathrm{~mm}$$. The transmitted light is collected on a screen $$100 \mathrm{~cm}$$ away. The distance of first order minima from the central maximum will be $$x \times 10^{-5} \mathrm{~m}$$. The value of $$x$$ is :
Answer
275
Explanation
$$\begin{aligned}
y & =\frac{n \lambda D}{a} \\
& =\frac{1 \times\left(550 \times 10^{-9}\right)(1)}{\left(0.2 \times 10^{-3}\right)} \\
& =275 \times 10^{-5} \mathrm{~m}
\end{aligned}$$
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