JEE MAIN - Physics (2024 - 5th April Evening Shift - No. 15)
The output (Y) of logic circuit given below is 0 only when :
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$$\mathrm{A}=0, \mathrm{~B}=0$$
$$\mathrm{A}=0, \mathrm{~B}=1$$
$$\mathrm{A}=1, \mathrm{~B}=0$$
$$\mathrm{A=1, B=1}$$
Explanation
$$\begin{aligned}
Y & =(A+B)+(B \cdot 1) \\
& =A+B+B \\
& =A+B
\end{aligned}$$
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