JEE MAIN - Physics (2024 - 4th April Evening Shift - No. 3)
Match List I with List II
| LIST I | LIST II |
||
|---|---|---|---|
| A. | Purely capacitive circuit | I. | _4th_April_Evening_Shift_en_3_1.png) |
| B. | Purely inductive circuit | II. | _4th_April_Evening_Shift_en_3_2.png) |
| C. | LCR series at resonance | III. | _4th_April_Evening_Shift_en_3_3.png) |
| D. | LCR series circuit | IV. | _4th_April_Evening_Shift_en_3_4.png) |
Choose the correct answer from the options given below:
A-IV. B-I, C-III, D-II
A-I. B-IV, C-II, D-III
A-IV. B-I, C-II, D-III
A-I. B-IV, C-III, D-II
Explanation
For pure capacitive circuit, $$I$$ lead by $$90^{\circ}$$ to $$\mathrm{V}$$
For pure inductive circuit, $$V$$ lead by $$90^{\circ}$$ to $$I$$
At series LCR resonance, $$I$$ and $$V$$ are in same phase.
For LCR series circuit, $$V$$ and I may suffer some phase difference.
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