JEE MAIN - Physics (2024 - 4th April Evening Shift - No. 2)
A $$2 \mathrm{~kg}$$ brick begins to slide over a surface which is inclined at an angle of $$45^{\circ}$$ with respect to horizontal axis. The co-efficient of static friction between their surfaces is:
1
1.7
0.5
$$\frac{1}{\sqrt{3}}$$
Explanation
$$\begin{aligned}
& m g \sin \theta=\mu \cdot m g \cos \theta \\
& \Rightarrow \tan \theta=\mu=1
\end{aligned}$$
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