JEE MAIN - Physics (2024 - 4th April Evening Shift - No. 14)

The translational degrees of freedom $$\left(f_t\right)$$ and rotational degrees of freedom $$\left(f_r\right)$$ of $$\mathrm{CH}_4$$ molecule are:

$$f_t=2$$ and $$f_r=2$$

$$f_t=3$$ and $$f_r=3$$

$$f_t=3$$ and 4$f_r=2$$

$$f_t=2$$ and $$f_r=3$$

For non-linear polyatomic molecules, both translational and rotational degree of freedom have same value and is equal to 3.