JEE MAIN - Physics (2024 - 4th April Evening Shift - No. 11)
A cyclist starts from the point $$P$$ of a circular ground of radius $$2 \mathrm{~km}$$ and travels along its circumference to the point $$\mathrm{S}$$. The displacement of a cyclist is:
_4th_April_Evening_Shift_en_11_1.png)
$$\sqrt8$$ km
4 km
6 km
8 km
Explanation
$$\begin{aligned}
\text { Displacement } & =\sqrt{2} R \\
& =\sqrt{8} \mathrm{~km}
\end{aligned}$$
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