JEE MAIN - Physics (2024 - 31st January Morning Shift - No. 27)
The mass defect in a particular reaction is $$0.4 \mathrm{~g}$$. The amount of energy liberated is $$n \times 10^7 \mathrm{~kWh}$$, where $$n=$$ __________. (speed of light $$\left.=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right)$$
Answer
1
Explanation
$$\begin{aligned}
& \mathrm{E}=\Delta \mathrm{mc}^2 \\
& =0.4 \times 10^{-3} \times\left(3 \times 10^8\right)^2 \\
& =3600 \times 10^7 \mathrm{kWs} \\
& =\frac{3600 \times 10^7}{3600} \mathrm{kWh}=1 \times 10^7 \mathrm{kWh}
\end{aligned}$$
Comments (0)
