JEE MAIN - Physics (2024 - 31st January Evening Shift - No. 3)

In a photoelectric effect experiment a light of frequency 1.5 times the threshold frequency is made to fall on the surface of photosensitive material. Now if the frequency is halved and intensity is doubled, the number of photo electrons emitted will be:
doubled
halved
Zero
quadrupled

Explanation

Since $$\frac{\mathrm{f}}{2}<\mathrm{f}_0$$

i.e. the incident frequency is less than threshold frequency. Hence there will be no emission of photoelectrons.

$$\Rightarrow \text { current }=0$$

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