JEE MAIN - Physics (2024 - 31st January Evening Shift - No. 20)
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The output of the given circuit diagram is -
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Explanation
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$$\begin{aligned} \text { If } \mathrm{A} & =0 ; \overline{\mathrm{A}}=1 \\ \mathrm{~A} & =1 ; \overline{\mathrm{A}}=0 \\ \mathrm{~B} & =0 ; \overline{\mathrm{B}}=1 \\ \mathrm{~B} & =1 ; \overline{\mathrm{B}}=0 \\ \mathrm{Y} & =\overline{(\mathrm{A}+\overline{\mathrm{B}})+(\overline{\mathrm{A}}+\mathrm{B})}=\overline{(1+1)}=0 \end{aligned}$$
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