JEE MAIN - Physics (2024 - 31st January Evening Shift - No. 18)
An AC voltage $$V=20 \sin 200 \pi t$$ is applied to a series LCR circuit which drives a current $$I=10 \sin \left(200 \pi t+\frac{\pi}{3}\right)$$. The average power dissipated is:
21.6 W
200 W
173.2 W
50 W
Explanation
$$\begin{aligned}
& <\mathrm{P}>=\mathrm{IV} \cos \phi \\
& =\frac{20}{\sqrt{2}} \times \frac{10}{\sqrt{2}} \times \cos 60^{\circ} \\
& =50 \mathrm{~W}
\end{aligned}$$
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