JEE MAIN - Physics (2024 - 31st January Evening Shift - No. 10)
A light string passing over a smooth light fixed pulley connects two blocks of masses $$m_1$$ and $$m_2$$. If the acceleration of the system is $$g / 8$$, then the ratio of masses is:
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$$\frac{8}{1}$$
$$\frac{9}{7}$$
$$\frac{5}{3}$$
$$\frac{4}{3}$$
Explanation
$$\begin{aligned}
& a=\frac{\left(m_1-m_2\right) g}{\left(m_1+m_2\right)}=\frac{g}{8} \\
& 8 m_1-8 m_2=m_1+m_2 \\
& 7 m_1=9 m_2 \\
& \frac{m_1}{m_2}=\frac{9}{7}
\end{aligned}$$
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