JEE MAIN - Physics (2024 - 30th January Morning Shift - No. 3)
Primary coil of a transformer is connected to $$220 \mathrm{~V}$$ ac. Primary and secondary turns of the transforms are 100 and 10 respectively. Secondary coil of transformer is connected to two series resistances shown in figure. The output voltage $$\left(V_0\right)$$ is :
_30th_January_Morning_Shift_en_3_1.png)
7 V
44 V
22 V
15 V
Explanation
$$\begin{aligned}
& \frac{\varepsilon_1}{\varepsilon_2}=\frac{N_1}{N_2}=\frac{100}{10} \Rightarrow \varepsilon_2=22 \mathrm{~V} \\
& I=\frac{22}{22 \times 10^3}=1 \mathrm{~mA}, V_0=7 \mathrm{~V}
\end{aligned}$$
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