JEE MAIN - Physics (2024 - 30th January Morning Shift - No. 23)

A electron of hydrogen atom on an excited state is having energy $$\mathrm{E}_{\mathrm{n}}=-0.85 \mathrm{~eV}$$. The maximum number of allowed transitions to lower energy level is _________.
Answer
6

Explanation

$$\begin{aligned} & E_n=-\frac{13.6}{n^2}=-0.85 \\ & \Rightarrow n=4 \end{aligned}$$

No of transition

$$=\frac{n(n-1)}{2}=\frac{4(4-1)}{2}=6$$

Comments (0)

Advertisement