JEE MAIN - Physics (2024 - 30th January Morning Shift - No. 22)
Two cells are connected in opposition as shown. Cell $$\mathrm{E}_1$$ is of $$8 \mathrm{~V}$$ emf and $$2 \Omega$$ internal resistance; the cell $$\mathrm{E}_2$$ is of $$2 \mathrm{~V}$$ emf and $$4 \Omega$$ internal resistance. The terminal potential difference of cell $$\mathrm{E}_2$$ is __________ V.
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Answer
6
Explanation
_30th_January_Morning_Shift_en_22_2.png)
$$I=\frac{8-2}{2+4}=\frac{6}{6}=1 \mathrm{~A}$$
Applying Kirchhoff from C to B
$$\begin{aligned} & V_C-2-4 \times 1=V_B \\\\ & V_C-V_B=6 \mathrm{~V} \\\\ & =6 \mathrm{~V} \end{aligned}$$
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