JEE MAIN - Physics (2024 - 30th January Morning Shift - No. 13)
A potential divider circuit is shown in figure. The output voltage V$$_0$$ is :
_30th_January_Morning_Shift_en_13_1.png)
2 mV
4 V
0.5 V
12 mV
Explanation
$$\begin{aligned}
& R_{e q}=4000 \Omega \\
& i=\frac{4}{4000}=\frac{1}{1000} \mathrm{~A} \\
& V_0=i . R=\frac{1}{1000} \times 500=0.5 \mathrm{~V}
\end{aligned}$$
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