JEE MAIN - Physics (2024 - 30th January Morning Shift - No. 12)
Match List I with List II.
| List I | List II | ||
|---|---|---|---|
| (A) | Coefficient of viscosity | (I) | $$\left[\mathrm{M} \mathrm{L}^2 \mathrm{~T}^{-2}\right]$$ |
| (B) | Surface tension | (II) | $$\left[\mathrm{M} \mathrm{L}^2 \mathrm{~T}^{-1}\right]$$ |
| (C) | Angular momentum | (III) | $$\left[\mathrm{M} \mathrm{L}^{-1} \mathrm{~T}^{-1}\right]$$ |
| (D) | Rotational kinetic energy | (IV) | $$\left[\mathrm{M} \mathrm{L}^0 \mathrm{~T}^{-2}\right]$$ |
Choose the correct answer from the options given below :
(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
Explanation
$$\begin{aligned}
& F=\eta A \frac{d v}{d y} \\
& {\left[M L T^{-2}\right]=\eta\left[L^2\right]\left[T^{-1}\right]} \\
& \eta=\left[M L^{-1} T^{-1}\right] \\
& S . T=\frac{F}{\ell}=\frac{\left[M L T^{-2}\right]}{[L]}=\left[M L^0 T^{-2}\right] \\
& L=m v r=\left[M L^2 T^{-1}\right] \\
& K . E=\frac{1}{2} I \omega^2=\left[M L^2 T^{-2}\right]
\end{aligned}$$
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