JEE MAIN - Physics (2024 - 30th January Morning Shift - No. 11)
At which temperature the r.m.s. velocity of a hydrogen molecule equal to that of an oxygen molecule at $$47^{\circ} \mathrm{C}$$ ?
20 K
80 K
4 K
$$-73$$ K
Explanation
$$\begin{aligned}
& \sqrt{\frac{3 R T}{2}}=\sqrt{\frac{3 R(320)}{32}} \\
& T=\frac{320}{16}=20 \mathrm{~K}
\end{aligned}$$
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