JEE MAIN - Physics (2024 - 30th January Evening Shift - No. 3)
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In the given circuit, the voltage across load resistance (R$$_L$$) is :
8.75 V
9.00 V
8.50 V
14.00 V
Explanation
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$$\begin{aligned} & \mathrm{i}=\frac{14}{4}=3.5 \mathrm{~mA} \\ & \mathrm{~V}_{\mathrm{L}}=\mathrm{iR}_{\mathrm{L}}=3.5 \times 2.5 \text { volt } \\ & \quad=8.75 \text { volt } \end{aligned}$$
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