JEE MAIN - Physics (2024 - 30th January Evening Shift - No. 23)
The current of $$5 \mathrm{~A}$$ flows in a square loop of sides $$1 \mathrm{~m}$$ is placed in air. The magnetic field at the centre of the loop is $$X \sqrt{2} \times 10^{-7} T$$. The value of $$X$$ is _________.
Answer
40
Explanation
$$\begin{aligned}
& \mathrm{B}=4 \times \frac{\mu_0 \mathrm{i}}{4 \pi(1 / 2)}\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\right) \\
& =4 \times 10^{-7} \times 5 \times 2 \times \sqrt{2} \\
& -40 \sqrt{2} \times 10^{-7} \mathrm{~T}
\end{aligned}$$
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