JEE MAIN - Physics (2024 - 30th January Evening Shift - No. 14)
Three blocks $$A, B$$ and $$C$$ are pulled on a horizontal smooth surface by a force of $$80 \mathrm{~N}$$ as shown in figure
The tensions T$$_1$$ and T$$_2$$ in the string are respectively :
40N, 64N
60N, 80N
80N, 100N
88N, 96N
Explanation
$$a_A=a_B=a_c=\frac{F}{5+3+2}=\frac{80}{10}=8 \mathrm{~m} / \mathrm{s}^2$$
$$\mathrm{T_1=5\times8=40}$$
$$\mathrm{T_2-T_1=3\times8\Rightarrow T_2=64}$$
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