JEE MAIN - Physics (2024 - 30th January Evening Shift - No. 11)
For the photoelectric effect, the maximum kinetic energy $$\left(E_k\right)$$ of the photoelectrons is plotted against the frequency $$(v)$$ of the incident photons as shown in figure. The slope of the graph gives
Planck's constant
Work function of the metal
Charge of electron
Ratio of Planck's constant to electric charge
Explanation
$$\begin{aligned}
& \text { K.E. }=\mathrm{hf}-\phi \\
& \tan \theta=\mathrm{h}
\end{aligned}$$
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