JEE MAIN - Physics (2024 - 30th January Evening Shift - No. 1)
If 50 Vernier divisions are equal to 49 main scale divisions of a traveling microscope and one smallest reading of main scale is $$0.5 \mathrm{~mm}$$, the Vernier constant of traveling microscope is
0.01 mm
0.01 cm
0.1 mm
0.1 cm
Explanation
$$\begin{aligned}
& 50 \mathrm{~V}+\mathrm{S}=49 \mathrm{~S}+\mathrm{S} \\
& \mathrm{S}=50(\mathrm{~S}-\mathrm{V}) \\
& 5=50(\mathrm{~S}-\mathrm{V}) \\
& \mathrm{S}-\mathrm{V}=\frac{0.5}{50}=\frac{1}{100}=0.01 \mathrm{~mm}
\end{aligned}$$
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