JEE MAIN - Physics (2024 - 29th January Morning Shift - No. 4)
The deflection in moving coil galvanometer falls from 25 divisions to 5 division when a shunt of $$24 \Omega$$ is applied. The resistance of galvanometer coil will be :
$$48 \Omega$$
$$100 \Omega$$
$$96 \Omega$$
$$12 \Omega$$
Explanation
Let x = current/division
_29th_January_Morning_Shift_en_4_1.png)
After applying shunt
_29th_January_Morning_Shift_en_4_2.png)
Now $$5 \mathrm{x} \times \mathrm{G}=20 \mathrm{x} \times 24$$
$$\begin{aligned} & \mathrm{G}=4 \times 24 \\ & \mathrm{G}=96 \Omega \end{aligned}$$
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