JEE MAIN - Physics (2024 - 29th January Morning Shift - No. 16)
In the given circuit, the breakdown voltage of the Zener diode is $$3.0 \mathrm{~V}$$. What is the value of $$\mathrm{I}_{\mathrm{z}}$$ ?
_29th_January_Morning_Shift_en_16_1.png)
3.3 mA
10 mA
5.5 mA
7 mA
Explanation
_29th_January_Morning_Shift_en_16_2.png)
$$\mathrm{V}_{\mathrm{z}}=3 \mathrm{~V}$$
Let potential at $$\mathrm{B}=0 \mathrm{~V}$$
Potential at $$E\left(V_E\right)=10 V$$
$$\begin{aligned} & V_C=V_A=3 V \\ & I_z+I_1=I \\ & I=\frac{10-3}{1000}=\frac{7}{1000} A \\ & I_1=\frac{3}{2000} A \end{aligned}$$
Therefore $$I_z=\frac{7-1.5}{1000}=5.5 \mathrm{~mA}$$
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