JEE MAIN - Physics (2024 - 29th January Morning Shift - No. 14)

Match List I with List II

List - I List - II
(A) $$\oint \vec{B} \cdot \overrightarrow{d l}=\mu_o i_c+\mu_o \varepsilon_o \frac{d \phi_E}{d t}$$ (I) Gauss' law for electricity
(B) $$\oint \vec{E} \cdot \overrightarrow{d l}=\frac{d \phi_B}{d t}$$ (II) Gauss' law for magnetism
(C) $$\oint \vec{E} \cdot \overrightarrow{d A}=\frac{Q}{\varepsilon_o}$$ (III) Faraday law
(D) $$\oint \vec{B} \cdot \overrightarrow{d A}=0$$ (IV) Ampere - Maxwell law

Choose the correct answer from the options given below:

A-IV, B-III, C-I, D-II
A-I, B-II, C-III, D-IV
A-IV, B-I, C-III, D-II
A-II, B-III, C-I, D-IV

Explanation

Ampere-Maxwell law

$$\rightarrow \oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{dl}}=\mu_0 \mathrm{i}_{\mathrm{c}}+\mu_0 \varepsilon_0 \frac{\mathrm{d} \phi_{\mathrm{E}}}{\mathrm{dt}}$$

Faraday law $$\rightarrow \oint \vec{E} \cdot \overrightarrow{d l}=\frac{d \phi_{\mathrm{B}}}{d t}$$

Gauss' law for electricity $$\rightarrow \oint \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{dA}}=\frac{\mathrm{Q}}{\varepsilon_0}$$

Gauss ' law for magnetism $$\rightarrow \oint \vec{B} \cdot \overrightarrow{d A}=0$$

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