JEE MAIN - Physics (2024 - 29th January Evening Shift - No. 5)
The truth table for this given circuit is :
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Explanation
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$$\begin{aligned} \mathrm{Y} & =\mathrm{A} \cdot \mathrm{B}+\overline{\mathrm{A}} \cdot \mathrm{B} \\ & =(\mathrm{A}+\overline{\mathrm{A}}) \cdot \mathrm{B} \\ \mathrm{Y} & =1 \cdot \mathrm{B} \\ \mathrm{Y} & =\mathrm{B} \end{aligned}$$
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