JEE MAIN - Physics (2024 - 29th January Evening Shift - No. 30)
A horizontal straight wire $$5 \mathrm{~m}$$ long extending from east to west falling freely at right angle to horizontal component of earths magnetic field $$0.60 \times 10^{-4} \mathrm{~Wbm}^{-2}$$. The instantaneous value of emf induced in the wire when its velocity is $$10 \mathrm{~ms}^{-1}$$ is _________ $$\times 10^{-3} \mathrm{~V}$$.
Answer
3
Explanation
$$\begin{aligned}
& \mathrm{B}_{\mathrm{H}}=0.60 \times 10^{-4} \mathrm{~Wb} / \mathrm{m}^2 \\
& \text { Induced emf e}=\mathrm{B}_{\mathrm{H}} \mathrm{v} \ell \\
&=0.60 \times 10^{-4} \times 10 \times 5 \\
&=3 \times 10^{-3} \mathrm{~V}
\end{aligned}$$
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