JEE MAIN - Physics (2024 - 27th January Morning Shift - No. 28)
Two long, straight wires carry equal currents in opposite directions as shown in figure. The separation between the wires is $$5.0 \mathrm{~cm}$$. The magnitude of the magnetic field at a point $$\mathrm{P}$$ midway between the wires is _______ $$\mu \mathrm{T}$$
(Given : $$\mu_0=4 \pi \times 10^{-7} \mathrm{TmA}^{-1}$$)
_27th_January_Morning_Shift_en_28_1.png)
Answer
160
Explanation
$$\begin{aligned}
& \mathrm{B}=\left(\frac{\mu_0 \mathrm{i}}{2 \pi \mathrm{a}}\right) \times 2=\frac{4 \pi \times 10^{-7} \times 10}{\pi \times\left(\frac{5}{2} \times 10^{-2}\right)} \\
& =16 \times 10^{-5}=160 \mu \mathrm{T}
\end{aligned}$$
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