JEE MAIN - Physics (2024 - 27th January Evening Shift - No. 4)
Primary side of a transformer is connected to $$230 \mathrm{~V}, 50 \mathrm{~Hz}$$ supply. Turns ratio of primary to secondary winding is $$10: 1$$. Load resistance connected to secondary side is $$46 \Omega$$. The power consumed in it is :
11.5 W
12.5 W
10.0 W
12.0 W
Explanation
$$\begin{aligned} & \frac{V_1}{V_2}=\frac{N_1}{N_2} \\ & \frac{230}{V_2}=\frac{10}{1} \\ & V_2=23 \mathrm{~V} \end{aligned}$$
Power consumed $$=\frac{\mathrm{V}_2^2}{\mathrm{R}}$$
$$=\frac{23 \times 23}{46}=11.5 \mathrm{~W}$$
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