JEE MAIN - Physics (2024 - 27th January Evening Shift - No. 19)
A current of $$200 \mu \mathrm{A}$$ deflects the coil of a moving coil galvanometer through $$60^{\circ}$$. The current to cause deflection through $$\frac{\pi}{10}$$ radian is :
120 $$\mu$$A
180 $$\mu$$A
30 $$\mu$$A
60 $$\mu$$A
Explanation
$$\mathrm{i} \propto \theta$$ (angle of deflection)
$$\begin{aligned} & \therefore \frac{\mathrm{i}_2}{\mathrm{i}_1}=\frac{\theta_2}{\theta_1} \Rightarrow \frac{\mathrm{i}_2}{200 \mu \mathrm{A}}=\frac{\pi / 10}{\pi / 3}=\frac{3}{10} \\ & \Rightarrow \mathrm{i}_2=60 \mu \mathrm{A} \end{aligned}$$
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