JEE MAIN - Physics (2024 - 27th January Evening Shift - No. 18)
The truth table of the given circuit diagram is :
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_27th_January_Evening_Shift_en_18_4.png)
_27th_January_Evening_Shift_en_18_5.png)
Explanation
_27th_January_Evening_Shift_en_18_6.png)
$$\mathrm{Y}=\mathrm{A} \cdot \overline{\mathrm{B}}+\overline{\mathrm{A}} \cdot \mathrm{B}$$
This is XOR GATE
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The truth table of the given circuit diagram is :
$$\mathrm{Y}=\mathrm{A} \cdot \overline{\mathrm{B}}+\overline{\mathrm{A}} \cdot \mathrm{B}$$
This is XOR GATE
