JEE MAIN - Physics (2024 - 1st February Morning Shift - No. 26)
A regular polygon of 6 sides is formed by bending a wire of length $4 \pi$ meter.
If an electric current of $4 \pi \sqrt{3}$ A is flowing through the sides of the polygon, the magnetic field at the centre of the polygon would be $x \times 10^{-7} \mathrm{~T}$.
The value of $x$ is _________.
If an electric current of $4 \pi \sqrt{3}$ A is flowing through the sides of the polygon, the magnetic field at the centre of the polygon would be $x \times 10^{-7} \mathrm{~T}$.
The value of $x$ is _________.
Answer
72
Explanation
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$\begin{aligned} & B=6\left(\frac{\mu_0 I}{4 \pi r}\right)\left(\sin 30^{\circ}+\sin 30^{\circ}\right) \\\\ & =6 \frac{10^{-7} \times 4 \pi \sqrt{3}}{\left(\frac{\sqrt{3} \times 4 \pi}{2 \times 6}\right)} \\\\ & =72 \times 10^{-7} \mathrm{~T}\end{aligned}$
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