JEE MAIN - Physics (2024 - 1st February Evening Shift - No. 5)
A galvanometer $(G)$ of $2 \Omega$ resistance is connected in the given circuit. The ratio of charge stored in $C_1$ and $C_2$ is :
_1st_February_Evening_Shift_en_5_1.png)
1
$\frac{2}{3}$
$\frac{3}{2}$
$\frac{1}{2}$
Explanation
_1st_February_Evening_Shift_en_5_2.png)
In steady state
$$ \begin{aligned} & { R_{eq} }=12 \Omega \\\\ & I=\frac{6}{12}=0.5 \mathrm{~A} \end{aligned} $$
P.D across $C_1=3 \mathrm{~V}$
P.D acoross $\mathrm{C}_2=4 \mathrm{~V}$
$$ \begin{aligned} & \mathrm{q}_1=\mathrm{C}_1 \mathrm{~V}_1=12 \mu \mathrm{C} \\\\ & \mathrm{q}_2=\mathrm{C}_2 \mathrm{~V}_2=24 \mu \mathrm{C} \end{aligned} $$
$$ \frac{\mathrm{q}_1}{\mathrm{q}_2}=\frac{1}{2} $$
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