JEE MAIN - Physics (2023 - 8th April Morning Shift - No. 15)
For the logic circuit shown, the output waveform at $$\mathrm{Y}$$ is:
_8th_April_Morning_Shift_en_15_1.png)
_8th_April_Morning_Shift_en_15_2.png)
_8th_April_Morning_Shift_en_15_3.png)
_8th_April_Morning_Shift_en_15_4.png)
_8th_April_Morning_Shift_en_15_5.png)
Explanation
$$
\begin{aligned}
&\text {For the given circuit the truth table would be : }\\\\
&\begin{array}{|c|c|c|}
\hline \mathbf{A} & \mathbf{B} & \mathbf{Y} \\
\hline 0 & 0 & 0 \\
\hline 0 & 1 & 1 \\
\hline 1 & 0 & 1 \\
\hline 1 & 1 & 1 \\
\hline
\end{array}
\end{aligned}
$$
The truth table shows that the output graph is given by :
_8th_April_Morning_Shift_en_15_6.png)
The truth table shows that the output graph is given by :
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